Prove that tan 7 degeree tan 23 degere tan 60 degere tan 67 degere tan 83 degree=/3
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Without using trigonometric tables, prove that : (i)tan48∘tan23∘tan42∘tan67∘= 1 (ii)tan7∘tan23∘tan60∘67∘tan83∘=√3
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Answer:
tan7°×tan23°×tan60°×tan67°×tan83°
1/cot7°×1/cot23°×tan60°×tan(90-23)×tan(90-7)
1/cot7°×1/cot23°×tan60°×cot23°×cot7°
tan60°
1/√3
proved
Step-by-step explanation:
hope it helps you
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