Prove that : tan 70= 2tan 50 + tan 20
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Answered by
367
According to the trigonometric identity,
tan70=tan(20+50)
tan70=(tan20+tan50)/1-tan20tan50
tan70-tan20tan50tan70=tan20+tan50
Also tan70tan20=tan70cot70=1
Hence
tan70-tan50=tan20+tan50
So tan70=tan20+2tan50
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Answered by
204
"According to the trigonometric identity,
tan70 = tan (20 + 50)
tan70= (tan20 + tan50) / 1-tan20 tan50
Tan70 - tan20 tan50 tan70= tan20 + tan50
Also tan70 tan20 = tan70 cot70 = 1
Hence, it will change to following equation
tan70 - tan50 = tan20 + tan50
So tan70 = tan20 + 2tan50
Complementary angles:
tan70=cot20
tan70tan20=cot20tan20=1
Tangent difference angle formula:
tan(a−b)=tana−tanb1+tanatanb
tan50=tan(70−20)=tan70−tan201+tan70tan20=tan70−tan201+1
2tan50=tan70−tan20
tan70=tan20+2tan50
"
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