prove that tan 8 theta - tan 6 theta - tan20 theta = tan 8 theta . tan 6 theta . tan 2 theta please answer i will mark them as brainlist
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I am taking theta as x for ease.
tan(8x) - tan(6x) - tan(2x)
tan(6x + 2x) - [ tan(6x) + tan(2x) ]
Since, tan(8x) when expanded,
[tan(6x) + tan(2x)] / [1 - tan(2x)tan(6x)]= tan(8x)
tan(6x) + tan(2x) = tan(8x).[ 1 - tan(2x)tan(6x) ]
Substitute this in the bold equation,
tan(8x) - tan(8x).[ 1 - tan(2x)tan(6x) ]
tan(8x) [ 1 - 1 + tan(2x)tan(6x) ]
tan(8x)tan(2x)tan(6x)
So, LHS + RHS
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