Question

prove that : tan (90-0) + cot (90-0) /cosec 0=sec A

​

Answer 1

Step-by-step explanation:

cosec(90

∘

−θ)sin(90

∘

−θ)cot(90

∘

−θ)

cos(90

∘

−θ)sec(90

∘

−θ)tanθ

+

cotθ

tan(90

∘

−θ)

=2

We know that,

cos(90−θ)=sinθ

sin(90−θ)=cosθ

tan(90−θ)=cotθ

cot(90−θ)=tanθ

sec(90−θ)=cscθ

csc(90−θ)=secθ

sec(θ)=

cos(θ)

1

and csc(θ)=

sin(θ)

1

secθcosθtanθ

sinθcscθtanθ

+

cotθ

cotθ

=2

secθcosθ

sinθcscθ

+1=2

sinθcosθ

sinθcosθ

+1=2

1+1=2

2=2

Hence proved