Math, asked by mraut3225, 17 hours ago

. Prove that

tan (90-0) + cot (90-0) /

cosec 0=

sec A​

Answers

Answered by AJ345678
2

Step-by-step explanation:

L.H.S

Since, tan (90°- 0) = cot 0

tan 0 + tan (90°-8)= tan 8 + cot 8

sin 0

cose

cose sin 0

sin² 8+cos² 0

sin 0 cose

Since,

sin²+ cos² 0 = 1 1

sin 0 cose 1

= X sin e

cose

= sec 0 cosec 0

Since,

cosec 0 sec (90° - 0)

= sec 0 sec (90° - 0)

= R.H.S

Hence, proved.

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