Math, asked by moumimukherjee, 1 year ago

prove that tan A / 1+secA+tanA/secA-1equall to 2/sinA


plzzz help me............by a correct ans as well as explanation​

Answers

Answered by kiran12355
0

Answer:

answer as shown in attachment ...hope u get it

Attachments:
Answered by devanshd0007
0

Answer:

LHS=1−sinA1+sinA

          =1−sinA1+sinA×1+sinA1+sinA

          =(1+sinA)(1−sinA)(1+sinA)2

          =1−sin2A(1+sinA)2

          =cos2A(1+sinA)2

          =(cosA1+sinA)2

          =cosA1+sinA

          =cosA1+cosAsinA

          =secA+tanA

          =RHS

Step-by-step explanation:

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