prove that tan A / 1+secA+tanA/secA-1equall to 2/sinA
plzzz help me............by a correct ans as well as explanation
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Answer:
answer as shown in attachment ...hope u get it
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Answer:
LHS=1−sinA1+sinA
=1−sinA1+sinA×1+sinA1+sinA
=(1+sinA)(1−sinA)(1+sinA)2
=1−sin2A(1+sinA)2
=cos2A(1+sinA)2
=(cosA1+sinA)2
=cosA1+sinA
=cosA1+cosAsinA
=secA+tanA
=RHS
Step-by-step explanation:
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