Math, asked by aryan1367, 1 year ago

prove that (tan A+2)(2 tan A +1)=5 tan A+ sec ^2A

Answers

Answered by sunitasingh0583

0

R.H.S
= 2 tan^2A + tanA + 4 tanA + 2
= 2 tan^2A + 2 + 5 tanA
= 2( tan ^2A + 1 ) + 5 tanA
= 2 sec^2A + 5 tanA = L.H.S.

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