Prove that :
tan(A+30) + tan(A-30) = 1/ sin 2A - sin60 ...
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4
Answer:
Step-by-step explanation:
hi there
LHS = tan(A + 30) + cot(A - 30)
= (tanA + tan 30/1 – tanA.tan30 ) + (cotA.cot 30 + 1/cot30 - cotA)
Write this in terms of sine and cosine.
On solving with this we get the ans. As => 2 / 4cosA.sinA - √3
= (1 / 2sinA.cosA) - (√3/2)
= 1 / (sin2A - sin 60)
= RHS
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MissLostGirl:
thank uh
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2
Tan230×sin30+cos60×sin290
=(1/root3)2×(½)+(½)×(1)2
=(1/3)×(1/2)+(1/2)
=(1/6)+(1/2)
=(1+3)/6
=4/6
=(1/root3)2×(½)+(½)×(1)2
=(1/3)×(1/2)+(1/2)
=(1/6)+(1/2)
=(1+3)/6
=4/6
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