Question

Prove that tan(A+B)/cot(A-B) = tan^2A - tan^2B / 1 - tan^2Atan^2B​

Answer 1

tan(A+B) = (tanA + tanB)/(1 - tanA tanB) ... ( 1 )

tan(A - B) = (tanA - tanB)/(1 + tanA tanB) ... ( 2 )

Multiplying eqns. ( 1 ) and ( 2 ),

tan(A + B) * tan(A - B) = (tan^2 A - tan^2 B) / (1 - tan^2 A * tan^2 B).

Answer 2

Step-by-step explanation:

Hence proved.............