prove that tan A+cot A = 2 cosec 2A
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Answer:
Step-by-step explanation:
LHS
= tan(A) + cot(A)
= sin(A)/cos(A) + cos(A)/sin(A)
= [sin²(A) + cos²(A)]/[sin(A) cos(A)]
= 1/[sin(A) cos(A)], since sin²(A) + cos²(A) = 1
= 1/[(1/2) sin(2A)], from the identity sin(2A) = 2 sin(A) cos(A)
= 2/sin(2A)
= 2 cosec(2A)
= RHS
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