Prove that (tan A + cotA)^2
= sec^2 A + cosec^2A
= secA.cosecA
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Answer:
LHS:-
(tanA+cotA)²=tan²A+cot²A+2
1+tan²A +1+cot²A
sec²A+cosec²A
1/cos²A +1/sin²A
(sin²A+cos²A)/sin²A.cos²A
1/sin²A.cos²A=sec²A.cosec²A
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