Math, asked by rekhamarri9876, 9 months ago


Prove that (tan A + cotA)^2
= sec^2 A + cosec^2A
= secA.cosecA ​

Answers

Answered by pal69
1

Answer:

LHS:-

(tanA+cotA)²=tan²A+cot²A+2

1+tan²A +1+cot²A

sec²A+cosec²A

1/cos²A +1/sin²A

(sin²A+cos²A)/sin²A.cos²A

1/sin²A.cos²A=sec²A.cosec²A

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