Question

prove that tan a divided by 1 minus cot A + cot a divided by 1 minus 10 is equal to 1 + 10 A + cot a is equal to 1 + sec cosec​

Answer 1

Step-by-step explanation:

The proof of the given equality is as follows :

tanA1−cotA+cotA1−tanA=sinAcosA1−cosAsinA+cosAsinA1−sinAcosA  

=sin2AcosA(sinA−cosA)+cos2AsinA(cosA−sinA)

=sin3A−cos3AcosAsinA(sinA−cosA)

=sin2A+cosAsinA+cos2AcosAsinA

=1+cosAsinAcosAsinA

=1+secAcscA.

tan A/1-cot A + cot A/1-tan A = 1+sec A cosec A

HENCE PROVED.

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