prove that tan A + sec A -1 / tanA-secA+1 = 1+sinA/cos A
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Step-by-step explanation:
LHS
tanA+secA-1/tanA-secA+1
=(tanA+secA)+(tan²A-sec²A)/tanA-secA+1
=(tanA+secA)+(tanA+secA)(tanA-secA)/ tanA-secA+1
=(tanA+secA)(1+tanA-secA)/
tanA-secA+1
=tanA+secA
=sinA/cosA+1/cosA
=1+sinA/cosA
RHS
thankyou
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