Math, asked by iuooooooooooo, 22 days ago

prove that . tan a+sina tan a−sina = seca−1 seca+1

Answers

Answered by singhmahima262

2

Step-by-step explanation:

tanA+sinAtanA−sinA

= sinAcosA+sinAsinAcosA−sinA

= sinA+cosA.sinAsinA−cosA.sinA

= sinA(1+cosA)sinA(1−cosA)

= 1+cosA1−cosA

Proved.

Also, 1+cosA1−cosA

= 1+1secA1−1secA

= secA+1secA−1

Proved.

Answered by cjsdnjvmmmmmmmmmmmm

1

Answer:

tanA+sinAtanA−sinA

= sinAcosA+sinAsinAcosA−sinA

= sinA+cosA.sinAsinA−cosA.sinA

= sinA(1+cosA)sinA(1−cosA)

= 1+cosA1−cosA

Proved.

Also, 1+cosA1−cosA

= 1+1secA1−1secA

= secA+1secA−1

Proved.

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