Question

Prove that:
tan A
tan A A
1+ sec A
2 cosec
А A
1- sech
$( prove \: that \: ) \frac{ \tan(a) }{1 + \sec(a) } - \frac{ \tan(a) }{1 - \sec(a) } = 2 \frac{ \sin(a) }{ \cos(a) }$
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Answer 1

Step-by-step explanation:

Actually now I can't see the question it's some code shown

Anyway just follow this steps

1 step convert tan A into sinA and cos A

by using identity tan A = sin A /cos A

2step take LCM you will get 1- sec² in dinominator

then simplify