Prove that tan alpha× tan beta/tan alpha +tan beta
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Let h be the height of aeroplane p above the road and A and B be two consecutive milestones. Then, AB=1 mile. Now in a ∆'s AQP and BQP , we have , tan alpha= h/AQ and tan bet a=h/BQ now ,AQ=hcot alpha and BQ= hcot bet a then, AQ +BQ= h(cot alpha + cot bet a) or, AB = h(tan alpha+ tan bet a/ tan alpha ×tan bet a) so, h = (tan alpha ×tan beta /tan alpha+tan bet a) .
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