Question

Prove that ,tan(B-C)+tan(C-A)+tan(A-B)=tan(B-C)tan(C-A)tan(A-B)

Answer 1

cosec A =1/sinA. sinA=1/cosecA cosA =1/secA sec A=1/cosA. sin A=1/cotA. cotA=1/sinA. I hope that this formula helps in doing this formula.