Prove that Tan inverse 1/7+ tan inverse 1\8=tan inverse 3\11
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we know that arc tan A+arc tan B=
arc tan (a+b/1-ab)
so, arc tan1/7+arc tan1/8=
arc tan (1/7+1/8/1-1/7×1/8)
arc tan(7+8/7×8/1-1/56)
arc tan(15/56/55/56)
arc tan(15/55)
arc tan(3/11).
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