Prove that tan inverse 1 + tan inverse 2 + tan inverse 3 equal to pi
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Step-by-step explanation:
⇒tan⁻¹(1)+tan⁻¹(2)+tan⁻¹(3)
tan⁻¹A+tan⁻¹B=tan(A+B/1-AB)
⇒tan⁻¹(1)+tan⁻¹(2)+tan⁻¹(3)
⇒tan⁻¹(1+2/1-(1*2))+tan⁻¹(3)
⇒tan⁻¹(-3)+tan⁻¹(3)
⇒tan⁻¹(-3+3/1-(-3*3))
⇒tan⁻¹(0)
⇒π
hence proved.
:)
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