Prove that tan inverse of tan 2a + tan inverse cot a + tan inverse cos cube equals to zero
Answers
Answered by
0
tan−1(2)+tan−1(3)=tan−1(
2+3
1−2⋅3
)=tan−1(−1)=nπ−
π
4
,
where n is any integer.
Now the principal value of tan−1(x) lies in [−
π
2
,
π
2
] precisely in (0,
π
2
) if finite x>0. So, the principal value of tan−1(2)+tan−1(3) will lie in (0,π).
So, the principal value of tan−1(2)+tan−1(3) will be
3π
4
.
Interestingly, the principal value of tan−1(−1) is −
π
4
.
But the general values of tan−1(2)+tan−1(3) and tan−1(−1) are same.
Alternatively,
tan−1(1)+tan−1(2)+tan−1(3)=tan−1(
1+2+3−1⋅2⋅3
1−1⋅2−2⋅3−3⋅1
)=tan−1(0)=mπ
, where m is any integer.
Now the principal value of tan−1(1)+tan−1(2)+tan−1(3) will lie in (0,
3π
2
) which is π.
The principal value of tan−1(0) is 0≠π.
Similar questions