Math, asked by user7932, 1 month ago

Prove that tan ø - cot ø ÷ sin ø - cos ø = tan² ø - cot² ø ​

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Answered by Salmonpanna2022
2

SOLUTION IS IN THE ATTACHMENT.

Trigonometry is the study of the relationship between the sides and angles of a triangle.

An equation involving trigonometry ratios of an angle is called is called a trigonometric identity, if it is true for all values of the angles involved. For any acute angle 0, we have the following identities.

i) sin² e + cos² θ = 1, ii) 1 + tan² θ = sec² θ, iii) cot² +1 = cosec² θ, iv) tan θ= sin θ/cos θ, v) cot = cos θ / sin SOLUTION IS IN THE ATTACHMENT.

Trigonometry is the study of the relationship between the sides and angles of a triangle.

An equation involving trigonometry ratios of an angle is called is called a trigonometric identity, if it is true for all values of the angles involved. For any acute angle 0, we have the following identities.

i) sin² e + cos² θ = 1, ii) 1 + tan² θ = sec² θ,

iii) cot² +1 = cosec² θ,

iv) tan θ= sin θ/cos θ, v) cot = cos θ / sin θ.

I hope it's help you...☺

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