Math, asked by preetdullat9328, 11 months ago

Prove that (tan#+sec#-1)/(tan#+1-sec#)=(1+cos#)/sin#

Answers

Answered by sandy1816

1

Step-by-step explanation:

tanA+secA-1/tanA-secA+1

=tanA+secA-(sec²A-tan²A)/tanA-secA+1

=(secA+tanA)(1-secA+tanA)/ (tanA-secA+1)

=secA+tanA

=1/cosA+sinA/cosA

=1+sinA/cosA

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