Question

Prove that (tan#+sec#-1)/(tan#+1-sec#)=(1+cos#)/sin#

Answer 1

Step-by-step explanation:

tan#+sec#-1/tan#-sec#+1

=tan#+sec#-(sec²#-tan²#)/tan#-sec#-1

=(sec#+tan#)(1-sec#+tan#)/tan#-sec#+1

=sec#+tan#

=(1+sin#)/cos#