Question

PROVE THAT

Tan/sec-1 = tan+sec+1/tan+sec-1

Answer 1

Answer:

1+tan*0=sec*0.....(identify)

tan*0=sec*-1

tan0×tan0=(sec0+1)(sec0-1

tan0/(sec0-1)=(sec0+1)/tan0

by theorem on equal ratios,

tan0/(sec0-1)=(sec0+1)/tan0=tan0+sec0+/sec0-1+tan0

tan0/sec0-1=tan0+sec0+1/tan0+sec0-l.

this you answer

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