Question

Prove that
tan+sine / tan-sine = sec +1 / seco-1​

Answer 1

Answer:

LHS ={tanA+sinA}{tanA-sinA}

tanA−sinA

tanA+sinA

= {sinA}{cosA})+1{sinA}{cosA})-1}

(

cosA

sinA

)−1

(

cosA

sinA

)+1

Take sinA common ,we get

={sinA{1}{cosA}+1)}{sinA{1}{cosA}-1)}

sinA(

cosA

1

−1)

sinA(

cosA

1

+1)

After cancellation of SinA , we get

= {secA+1}{secA-1}

secA−1

secA+1

/* 1/cosA = secA */

= RHS

Answer 2

Answer:

I Hope it helps........