Prove that tan square 30degree+tan square 45degree+tan square 60degree=13 upon 3
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Hey dear friend
Tan²30°+Tan²45°+Tan²60°=13/3
Tan30°=1/✓3
Tan45°=1
Tan60°=✓3
Substituting all values
=>(1/✓3)²+(1)²+(✓3)²
=>1/3+1+3
=>1+3+9/3
=>13/3
13/3=R.H.S.
Hence Proved
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Tan²30°+Tan²45°+Tan²60°=13/3
Tan30°=1/✓3
Tan45°=1
Tan60°=✓3
Substituting all values
=>(1/✓3)²+(1)²+(✓3)²
=>1/3+1+3
=>1+3+9/3
=>13/3
13/3=R.H.S.
Hence Proved
Be PERFECTIONIST
hope it helps you mark me as brainliest and follow me
Answered by
2
LHS = tan²A - sin²A
= ( sin²A/cos²A ) - sin²A
= sin²A [ 1/cos²A - 1 ]
= sin²A( sec²A - 1 )
= sin²A tan²A
[ since , sec²A - 1 = tan²A ]
= tan²Asin²A
= RHS
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