Question

prove that tan squared theta minus sin square theta equal to tan square theta into sin square theta​

Answer 1

Step-by-step explanation:

$\tan{}^{2} \alpha - \sin { \alpha }^{2} = \tan {}^{2} \times \sin {}^{2}$

RHS

$\tan{}^{2} \alpha (1 - \cos {}^{2} \alpha )$

$\tan{}^{2} \alpha - \tan {}^{2} \alpha \times \cos{}^{2} \alpha$

$\tan{}^{2} \alpha - \sin {}^{2} \alpha \div \cos{}^{2} \alpha \times \cos {}^{2} \alpha$

$\tan{}^{2} \alpha - \sin{}^{2} \alpha$

proved