prove that tan teta + sec teta -1 / tan teta - sec teta + 1 = 1 + sin teta / cos teta
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Step-by-step explanation:
tanA+secA-1/tanA-secA+1
=(tanA+secA)-(sec²A-tan²A)/(tanA-secA+1)
=(secA+tanA)(1-secA+tanA)/(tanA-secA+1)
=secA+tanA
=1+sinA/cosA
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