Question

Prove that
Tan theta +1/Tan theta =sec2 theta

Answer 1

UR QUESTION IS WRONG WE HAVE TO PROVE IT EQUAL TO COSEC THETA

Answer 2

       

I think your question is wrong and is as the following:

$\sf{Prove\ that}\ \ \tan\theta+\frac{1}{\tan\theta}=\sec\theta \cdot \csc\theta$

Okay, I'm proving this.

$\tan\theta+\frac{1}{\tan\theta} \\ \\ \\ \frac{\tan^2\theta+1}{\tan\theta} \\ \\ \\ \frac{\sec^2\theta}{\tan\theta}\ \ \ \ \ [\sec^2\theta-\tan^2\theta=1\ \ \ ; \ \ \ \sec^2\theta=\tan^2\theta+1] \\ \\ \\ \frac{\sec\theta}{\tan\theta} \ \cdot \ \sec\theta \\ \\ \\ \csc\theta \ \cdot \ \sec\theta \ \ \ \ \ [\tan\theta=\frac{\sec\theta}{\csc\theta}\ \ \ ; \ \ \ \csc\theta=\frac{\sec\theta}{\tan\theta}]$

Hope this helps.

Plz mark it as the brainliest.

Thank you. :-))