Math, asked by akchy001, 3 months ago

prove that:- (tan theta + cot theta)^2 = (tan^2 theta + 1) (cot^2 theta + 1) .​

Answers

Answered by prabhat311
1

Answer

Prove that: 1 + tan^2Θ/1 + cot^2Θ = (1 - tanΘ/1 - cotΘ)^2 = tan^2Θ

1 + tan^2theta1 + cot^2theta = 1 + tan^2theta1 + 1tan^2theta ( 1 - tantheta1 - cottheta )^2 = 1 + tan^2theta (tan^2theta+1tan^2theta) = ( 1 - tantheta1 ...  

Similar questions