prove that tan theta+cot theta=sec theta-cosec theta
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Answered by
5
Answer:
In R. H. S
cot A+tan A
we can write this as cos A ÷ sin A +sin A ÷ cosA
so,
cosA²+sinA²÷sinA*×cosA
cos A²+sinA²=1
1÷sinA×cosA
now,
1÷sinA×1÷cosA
cosecA × secA
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Answered by
1
LHS=tan theta + cot theta
proof:
sin theta/cos theta + cos theta / sin theta
sin^2 + cos^2 / cos theta × sin theta
1/ cos ×sin
1/cos 1/ sin
= sec theta cosec theta
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