prove that (tan theta + sec theta -1)/(tan theta - sec theta +1) =(1+sin theta)/cos theta
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Step-by-step explanation:
Let, theta=A
tanA+secA-1/tanA-secA+1=1+sinA/cosA
L.H.S.— tanA+secA-1/tanA-secA+1
=(tanA+secA)-(sec²A-tan²A)/tanA-secA+1
[1=sec²A-tan²A]
=(tanA+secA)-(secA+tanA)(secA-tanA)/tanA-secA+1
=(tanA+secA){1-(secA-tanA)}/tanA-secA+1
=(tanA+secA)(1-secA+tanA)/tanA-secA+1
=tanA+secA
=sinA/cosA+1/cosA
=sinA+1/cosA
=R.H.S.
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