Prove That : (tan theta + sec theta -1)(tan theta + sec theta +1)=2 sin theta/1 - sin theta
Answers
tan@ + sec@ + 1 = (sin@ + cos@ + 1) / cos@
Concept
The process of measuring angles relating to angles are covered in the fundamentals of trigonometry. Trigonometry has three fundamental operations: sine, cosine, and tangent. The cotangent, secant, and cosecant are three crucial trigonometric functions that can be derived from these three fundamental ratios or functions.
Given
(tanθ ₊ secθ ₋ 1)(tanθ ₊ secθ ₊ 1) = 2sinθ / 1₋sin²θ
Find
we need to prove the above given expression.
Solution
L.H.S = (tanθ ₊ secθ ₋ 1)(tanθ ₊ secθ ₊ 1)
multiply the above terms.
= tan²θ ₊ tanθsecθ ₊ tanθ ₊ secθtanθ ₊ sec²θ ₊ secθ ₋ tanθ ₋ secθ ₋ 1
cancelling like terms.
= tan²θ ₊ tanθsecθ ₊ sec²θ ₊ secθtanθ
= tan²θ ₊ sec²θ ₊ 2 tanθsecθ ₋ 1
using the identity tan²θ ₊ sec²θ = 1
= 1 ₊ 2 tanθsecθ ₋ 1
= 2 tanθsecθ
= 2 sinθ/cosθ × 1/cosθ
= 2sinθ/cos²θ
= 2sinθ/1₋sin²θ
= R.H.S
hence, proved
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your question was incomplete. Please find the missing content below.
prove that : (tanθ ₊ secθ ₋ 1)(tanθ ₊ secθ ₊ 1) = 2sinθ / 1₋sin²θ