prove that tan theta × tan (60- theta) tan (60+theta)=tan3theta
Answers
Answered by
2
Answer:
Step-by-step explanation:
LHS = tanA +[ [tanA+sqrt3] / [1-{(sqrt3)tanA)}] ] +[ [tanA-sqrt3] / [1+[sqrt3}tanA ] ]
ON solving
=> tanA + [8tanA /(1-3sqtanA)]
=> 9tanA-3cubetanA / [1-3sqtanA]
=> 3tan3A = RHS
hope this may help u...
vinu9232:
3tan3A is the wrong answer
3tanA is the correct answer
sorry
tan3theta is the answer
sorry for that
i will give the correct one
ok
Similar questions