Prove that :
tan theta + tan π - theta + cot ( π/2 + theta ) - tan ( 2π-theta ) = 0
Please help me.
Answers
Answered by
0
Answer:
L.H.S= tanθ + [- tanθ] - tanθ + tanθ
L.H.S = tanθ - tanθ - tanθ + tanθ
L.H.S = 0 = R.H.S
Hope this helps ya!
Answered by
0
Answer:
is it help you ❓❤️
GIVE THANKS=❤️
Attachments:
Similar questions