Question

Prove that :

tan theta + tan π - theta + cot ( π/2 + theta ) - tan ( 2π-theta ) = 0

Please help me. ​

Answer 1

Answer:

L.H.S= tanθ + [- tanθ] - tanθ + tanθ

L.H.S = tanθ - tanθ - tanθ + tanθ

L.H.S = 0 = R.H.S

Hope this helps ya!

Answer 2

Answer:

is it help you ❓❤️

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