Prove that tan tita / 1+cot tita + cot tita / 1+tan tita = 1 + sec tita × cosec tita
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tanA1−cotA+cotA1−tanA=sinAcosA1−cosAsinA+cosAsinA1−sinAcosA
=sin2AcosA(sinA−cosA)+cos2AsinA(cosA−sinA)
=sin3A−cos3AcosAsinA(sinA−cosA)
=sin2A+cosAsinA+cos2AcosAsinA
=1+cosAsinAcosAsinA
=1+secAcscA.
Step-by-step explanation:
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