prove that tan tita+2tan2tita+4tan4tita+8cot8tita=cot tita
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Answer:
By definition
cot
(
θ
)
=
1
tan
(
θ
)
Explanation:
tan
(
θ
)
⋅
cot
(
θ
)
=
tan
(
θ
)
⋅
1
tan
(
θ
)
=
tan
(
θ
)
⋅
1
tan
(
θ
)
=
1
Step-by-step explanation:
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