Question

Prove that
tan x/secx+1 +secx+1/tanx = 2cosecx​

Answer 1

Step-by-step explanation:

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Answer 2

$\frac{tanx}{secx + 1} + \frac{secx + 1}{tanx} \\ \\ = \frac{ {tan}^{2} x + ( {secx + 1)}^{2} }{tanx(secx + 1)} \\ \\ = \frac{2 {sec}^{2}x + 2secx }{tanx(secx + 1)} \\ \\ = 2 \frac{secx}{tanx} \\ \\ = 2cosecx$