prove that tan0+sin0/tan0-sin0=1+cos0/1-cos0
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Answer:
since sin= p/h
therefore p= 4x
h= 5x
b= under root 5x^2 -4x^2=under root 25x^2 - 16x^2=under root 9x^2= 3x
therefore,
cos = b/h =3x/5x = 3/5
tan = p/b = 4x/3x = 4/3
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