prove that tan1.tan2.tan3....................tan89=1
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tan 1 . tan 2 . tan 3 ........ tan 89
We can write the above problem like this :
tan 1 tan 89 . tan 2 tan 88 . ..............................
Note that we are multiplying the last element with the first one and then we are moving onto the next element from the last .
tan 1 . tan 89 . tan 2 tan 88 ......
Now tan ( 90 - A ) = cot A
So tan 1 = tan ( 90 - 89 ) = cot 89 .
Hence tan 2 = tan ( 90 - 88 ) = cot 88 .
Like this every element will be replaced :
cot 89 . tan 89 . cot 88 . tan 88 ......................
We know that cot A tan A = 1
This means that every multiplication product will be equal to 1 :
1 . 1 . .................
= > 1
The final answer will be 1 because every element will be equal to 1 when arranged like that !
Hence Proved.
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