Math, asked by SSochan, 2 months ago

prove that tan10°.tan25°.tan45°tan65°tan80°=1​

Answers

Answered by nishi373
5

Answer:

Answer:

L.H.S. = tan 10˚ tan 15˚ tan 75˚ tan 80˚

= tan 10˚ tan 15˚ tan (90˚ – 15˚) tan(90˚ – 10˚)

= tan 10˚ tan 15˚ cot 15˚ cot 10˚

1/cot10˚ × 1/cot 15˚ × cot 15˚ × cot 10˚

= 1 = R.H.S.

Hence proved.

(ii) L.H.S. = cos 1˚ cos 2˚ cos 3˚ …..cos 180˚

= cos1˚ cos2˚ cos 3˚ …..cos 89˚ cos 90˚ ….cos 180˚

= cos 1˚ cos 2˚ cos 3˚ ….cos 89˚ × 0 × cos 91˚ ….cos 180˚

= 0 = R.H.S.

Hence proved.

Step-by-step explanation:

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Step-by-step explanation:

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Answered by ratnala380
3

Answer:

L.H.S. = tan 10˚ tan 15˚ tan 75˚ tan 80˚

= tan 10˚ tan 15˚ tan (90˚ – 15˚) tan(90˚ – 10˚)

= tan 10˚ tan 15˚ cot 15˚ cot 10˚

1/cot10˚ × 1/cot 15˚ × cot 15˚ × cot 10˚

= 1 = R.H.S.

Hence proved.

(ii) L.H.S. = cos 1˚ cos 2˚ cos 3˚ …..cos 180˚

= cos1˚ cos2˚ cos 3˚ …..cos 89˚ cos 90˚ ….cos 180˚

= cos 1˚ cos 2˚ cos 3˚ ….cos 89˚ × 0 × cos 91˚ ….cos 180˚

= 0 = R.H.S.

Hence proved.

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