Prove that tan15° =2- square root3
Answers
Answered by
1
tan15 = tan(45-30) = tan45-tan30/1+tan45tan30
∵tan(A-B) =tanA+tanB/1+tanAtanB
⇒ (1-1/√3)/(1+1/√3)
⇒√3-1/√3+1
⇒2-√3
∵tan(A-B) =tanA+tanB/1+tanAtanB
⇒ (1-1/√3)/(1+1/√3)
⇒√3-1/√3+1
⇒2-√3
Similar questions