prove that tan² A -tan² B = Cos² B - cos² A / cos² A . cos² B
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Answer:
RHS = cos²B / cos²A cos²B - cos²A / cos²A cos²B
= 1/cos²A - 1/cos²B
= sec²A - sec²B
= 1 + tan²A - 1 - tan²B
= tan²A - tan²B = LHS
hence proved
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