Question

prove that tan² q / (sec q -1)² = 1 + cos q / 1 - cos ​

Answer 1

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Answer 2

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$(1 + \tan {}^{2} ) \: (1 - \sin)(1 + \sin) \\ = ( \sec {}^{2} \: )( 1 - \sin)$

$( \sec {}^{2} \: )( \cos {}^{2} )$

$( \sec {}^{2} ) \: \frac{1}{ \sec}$

$= 1$