Math, asked by yogirajmaliya2765, 10 months ago

Prove that tan²∅-sin²∅=sin⁴∅sec²∅

Answers

Answered by sandy1816

1

Step-by-step explanation:

tan²A-sin²A=sin⁴Asec²A

LHS

tan²A-sin²A

=sin²A/cos²A-sin²A

=sin²A-sin²Acos²A/cos²A

=sin²A-sin²A(1-sin²A)/cos²A

=sin²A-sin²A+sin⁴A/cos²A

=sin⁴A/cos²A

=sin⁴Asec²A

thankYou

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