Prove that tan²θ−sin²θ= sin⁴θsec²θ
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ANSWER:
To Prove:
- tan²θ − sin²θ = sin⁴θsec²θ
Solution:
We need to prove that,
Taking LHS,
We know that,
So,
Taking sin²θ common,
Taking LCM,
We know that,
Hence,
We also know that,
So,
Hence,
As, LHS = RHS
HENCE PROVED!!!
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