prove that tan² tetha +cot²tetha + 2 = sec² tetha × cosec²tetha
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Step-by-step explanation:
consider that theta as x
[tex]tan^{2}x + cot^{2} x + 2 = 1 + {tan}^{2} x + 1 + {cot}^{2} x \\ = {sec}^{2} x + cosec ^{2} x[/tex
sec sq.x +cosec sq.x=(1/cos sq.x)+(1/sin sq.x)=secsq.xcisecsq.x
by substitution it will proved
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