Prove that (tan²0-sin²O) = tan’²Osin²0
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what to prove = ?
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Hi there !!
Identity used {0 = thetha}
- 1/cos²0 = sec²0
- tan²0 = sin²0/cos²0
- sec²0 -1 = tan²0
Look at the attachment. ↑
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Answered by
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Answer:
1/cos²0 = sec²0
tan²0 = sin²0/cos²0
sec²0 -1 = tan²0
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