Prove that tan20tan40tan60tan80=3
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√3 tan 20 tan (60 - 20) tan (60 + 20)
√3 tan 20 ( √3 - tan 20 / 1+ √3 tan 20) (√3 + tan 20 / 1 - √3 tan 20 )
√3 ( 3 tan 20 - tan^3 20 / 1 - 3 tan ^2 20)
√3 tan (3 * 20)
√3 tan 60 tan 80 = 3
√3 tan 20 ( √3 - tan 20 / 1+ √3 tan 20) (√3 + tan 20 / 1 - √3 tan 20 )
√3 ( 3 tan 20 - tan^3 20 / 1 - 3 tan ^2 20)
√3 tan (3 * 20)
√3 tan 60 tan 80 = 3
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