prove that..tan20tan40tan80=√3
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Hey dear :D
Apply the formula , that is -
tan¢ . tan ( 60 - ¢) . tan (60 + ¢ ) = tan 3 ¢
Substitute the values
tan 20. tan (60-20) . tan (60 + 20) = tan 3 ×20
tan 20. tan 40. tan 80 = tan 60
tan 20. tan 40. tan 80 = √3
hence proved!
hope it helps!! ^^
Apply the formula , that is -
tan¢ . tan ( 60 - ¢) . tan (60 + ¢ ) = tan 3 ¢
Substitute the values
tan 20. tan (60-20) . tan (60 + 20) = tan 3 ×20
tan 20. tan 40. tan 80 = tan 60
tan 20. tan 40. tan 80 = √3
hence proved!
hope it helps!! ^^
protham:
but I want to use this formula.. tan(A+B)tanA+tanB/1-tanAtanB
sorry..it is tan(A+B)=........
that can also be applies
applied*
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